CWE-457: Use of Uninitialized Variable
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Edit Custom FilterThe code uses a variable that has not been initialized, leading to unpredictable or unintended results.
In some languages such as C and C++, stack variables are not initialized by default. They generally contain junk data with the contents of stack memory before the function was invoked. An attacker can sometimes control or read these contents. In other languages or conditions, a variable that is not explicitly initialized can be given a default value that has security implications, depending on the logic of the program. The presence of an uninitialized variable can sometimes indicate a typographic error in the code.
This table specifies different individual consequences
associated with the weakness. The Scope identifies the application security area that is
violated, while the Impact describes the negative technical impact that arises if an
adversary succeeds in exploiting this weakness. The Likelihood provides information about
how likely the specific consequence is expected to be seen relative to the other
consequences in the list. For example, there may be high likelihood that a weakness will be
exploited to achieve a certain impact, but a low likelihood that it will be exploited to
achieve a different impact.
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Relevant to the view "Research Concepts" (CWE-1000)
Relevant to the view "CISQ Quality Measures (2020)" (CWE-1305)
Relevant to the view "CISQ Data Protection Measures" (CWE-1340)
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given
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Languages C (Sometimes Prevalent) C++ (Sometimes Prevalent) Perl (Often Prevalent) PHP (Often Prevalent) Class: Not Language-Specific (Undetermined Prevalence) Example 1 This code prints a greeting using information stored in a POST request: (bad code)
Example Language: PHP
if (isset($_POST['names'])) {
$nameArray = $_POST['names']; }echo "Hello " . $nameArray['first']; This code checks if the POST array 'names' is set before assigning it to the $nameArray variable. However, if the array is not in the POST request, $nameArray will remain uninitialized. This will cause an error when the array is accessed to print the greeting message, which could lead to further exploit. Example 2 The following switch statement is intended to set the values of the variables aN and bN before they are used: (bad code)
Example Language: C
int aN, Bn;
switch (ctl) { case -1:
aN = 0;
bN = 0; break; case 0: aN = i;
bN = -i; break; case 1: aN = i + NEXT_SZ;
bN = i - NEXT_SZ; break; default: aN = -1;
aN = -1; break; repaint(aN, bN); In the default case of the switch statement, the programmer has accidentally set the value of aN twice. As a result, bN will have an undefined value. Most uninitialized variable issues result in general software reliability problems, but if attackers can intentionally trigger the use of an uninitialized variable, they might be able to launch a denial of service attack by crashing the program. Under the right circumstances, an attacker may be able to control the value of an uninitialized variable by affecting the values on the stack prior to the invocation of the function. Example 3 This example will leave test_string in an unknown condition when i is the same value as err_val, because test_string is not initialized (CWE-456). Depending on where this code segment appears (e.g. within a function body), test_string might be random if it is stored on the heap or stack. If the variable is declared in static memory, it might be zero or NULL. Compiler optimization might contribute to the unpredictability of this address. (bad code)
Example Language: C
char *test_string;
if (i != err_val) { test_string = "Hello World!";
}printf("%s", test_string); When the printf() is reached, test_string might be an unexpected address, so the printf might print junk strings (CWE-457). To fix this code, there are a couple approaches to making sure that test_string has been properly set once it reaches the printf(). One solution would be to set test_string to an acceptable default before the conditional: (good code)
Example Language: C
char *test_string = "Done at the beginning";
if (i != err_val) { test_string = "Hello World!";
}printf("%s", test_string); Another solution is to ensure that each branch of the conditional - including the default/else branch - could ensure that test_string is set: (good code)
Example Language: C
char *test_string;
if (i != err_val) { test_string = "Hello World!";
}else { test_string = "Done on the other side!";
}printf("%s", test_string);
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